What is the derivative of (x^2-3/(x^2-4)) ?

The derivative of (x^2-3/(x^2-4)) is -(2x)/((x^2-4)^2)

What is the first derivative of (x^2-3/(x^2-4)) ?

The first derivative of (x^2-3/(x^2-4)) is -(2x)/((x^2-4)^2)

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Popular >

\frac{d}{d x} (\frac{x ^{2} - 3}{x ^{2} - 4})

- \frac{2 x}{( x ^{2} - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 3}{x ^{2} - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 3 ) ( x ^{2} - 4 ) - \frac{d}{d x} ( x ^{2} - 4 ) ( x ^{2} - 3 )}{( x ^{2} - 4 ) ^{2}}

\frac{d}{d x} (x^{2} - 3) = 2 x

\frac{d}{d x} (x^{2} - 4) = 2 x

= \frac{2 x ( x ^{2} - 4 ) - 2 x ( x ^{2} - 3 )}{( x ^{2} - 4 ) ^{2}}

Simplify

\frac{2 x ( x ^{2} - 4 ) - 2 x ( x ^{2} - 3 )}{( x ^{2} - 4 ) ^{2}} : - \frac{2 x}{( x ^{2} - 4 ) ^{2}}

= - \frac{2 x}{( x ^{2} - 4 ) ^{2}}

[\frac{3 + s}{( s + 1 ) ^{2}}]

1000

x \to 0 lim (\frac{8 ^{x} - 1 0 ^{x}}{x})

y = \frac{4 x}{3}

n = 1 \sum \infty (\frac{1}{2})^{n}

What is the derivative of (x^2-3/(x^2-4)) ?
The derivative of (x^2-3/(x^2-4)) is -(2x)/((x^2-4)^2)
What is the first derivative of (x^2-3/(x^2-4)) ?
The first derivative of (x^2-3/(x^2-4)) is -(2x)/((x^2-4)^2)