What is (\partial)/(\partial y)(x^3+y^2) ?

The answer to (\partial)/(\partial y)(x^3+y^2) is 2y

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(\partial)/(\partial y)(x^3+y^2)

\frac{\partial}{\partial y} (x^{3} + y^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (x^{3} + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{3}) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (x^{3}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 + 2 y

Simplify

= 2 y

x \to 0 lim ((1 + a x)^{\frac{a}{x}})

x = 3 - 3 y^{2}, x = 3 y^{2} - 3

\int \frac{2 x}{( x - 5 ) ^{2}} d x

\frac{d}{d x} (ln (4 + 5 x))

\frac{d}{d x} (a x^{n} + cy (x)^{n})

What is (\partial)/(\partial y)(x^3+y^2) ?
The answer to (\partial)/(\partial y)(x^3+y^2) is 2y