What is the integral from 1 to 2 of ln(3)x^2 ?

The integral from 1 to 2 of ln(3)x^2 is ln(3) 7/3

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integral from 1 to 2 of ln(3)x^2

\int_{1}^{2} ln (3) x^{2} d x

ln (3) \frac{7}{3}

Decimal

2.56342 \dots

Solution steps

\int_{1}^{2} ln (3) x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= ln (3) \cdot \int_{1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{2}

= ln (3) [\frac{x ^{3}}{3}]_{1}^{2}

Compute the boundaries:

\frac{7}{3}

= ln (3) \frac{7}{3}

\frac{d y}{d x} = \frac{x - 4}{y + 3}

\int \frac{x}{( x ^{2} + x + 1 )} d x

\frac{d}{d x} (sin (x) \cdot ln (x))

x \to 1 lim (\frac{x ^{2} - 1}{1 - x})

\frac{1}{x - 1}, 20

What is the integral from 1 to 2 of ln(3)x^2 ?
The integral from 1 to 2 of ln(3)x^2 is ln(3) 7/3