What is the integral of 3e^{x^3} ?

The integral of 3e^{x^3} is 3(-(x\Gamma(1/3 ,-x^3))/(3\sqrt[3]{-x^3)})+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3e^{x^3}

\int 3 e^{x^{3}} d x

3 (- \frac{x Γ ( \frac{1}{3} , - x ^{3} )}{3 3 - x ^{3}}) + C

Solution steps

\int 3 e^{x^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int e^{x^{3}} d x

Use the nonelementary integral:

\int e^{x^{a}} d x = - \frac{x Γ ( \frac{1}{a} , - x ^{a} )}{a a - x ^{a}}

= 3 (- \frac{x Γ ( \frac{1}{3} , - x ^{3} )}{3 3 - x ^{3}})

Add a constant to the solution

= 3 (- \frac{x Γ ( \frac{1}{3} , - x ^{3} )}{3 3 - x ^{3}}) + C

\int_{0}^{x} x e^{- x} d x

f (x) = \frac{x}{( 3 x - 8 ) ^{6}}, at x = 3

\frac{d}{d x} ((5 - 2 x)^{5})

f (t) = t + 4

x \to 0 + lim (\frac{x ^{2}}{6} - \frac{5}{x})

What is the integral of 3e^{x^3} ?
The integral of 3e^{x^3} is 3(-(x\Gamma(1/3 ,-x^3))/(3\sqrt[3]{-x^3)})+C