What is the limit as x approaches infinity of 2^x-1 ?

The limit as x approaches infinity of 2^x-1 is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches infinity of 2^x-1

x \to \infty lim (2^{x} - 1)

\infty

Solution steps

x \to \infty lim (2^{x} - 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (2^{x}) - x \to \infty lim (1)

x \to \infty lim (2^{x}) = \infty

x \to \infty lim (1) = 1

= \infty - 1

Apply Infinity Property:

\infty - c = \infty

= \infty

\frac{d}{d x} (4 e^{- x^{4}})

\int w^{2} ln (w^{6} - 1) d w

\int \frac{1 - y ^{2}}{3 y} d y

y^{^{''}} + y = x^{2} + 1

\int \frac{8}{x ^{4} + 4} d x

What is the limit as x approaches infinity of 2^x-1 ?
The limit as x approaches infinity of 2^x-1 is infinity