What is the d/(dt)((arccos(t))^2) ?

The d/(dt)((arccos(t))^2) is -(2arccos(t))/(sqrt(1-t^2))

What is the first d/(dt)((arccos(t))^2) ?

The first d/(dt)((arccos(t))^2) is -(2arccos(t))/(sqrt(1-t^2))

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\frac{d}{d t} ((arccos (t))^{2})

- \frac{2 arccos ( t )}{1 - t ^{2}}

Solution steps

\frac{d}{d t} ((arccos (t))^{2})

Apply the chain rule:

2 arccos (t) \frac{d}{d t} (arccos (t))

= 2 arccos (t) \frac{d}{d t} (arccos (t))

\frac{d}{d t} (arccos (t)) = - \frac{1}{1 - t ^{2}}

= 2 arccos (t) (- \frac{1}{1 - t ^{2}})

Simplify

2 arccos (t) (- \frac{1}{1 - t ^{2}}) : - \frac{2 arccos ( t )}{1 - t ^{2}}

= - \frac{2 arccos ( t )}{1 - t ^{2}}

\int 2 cos^{3} (4 x) d x

\frac{\partial}{\partial v} (2 uv)

\frac{f ( x )}{x ^{7}}

x \to 0 lim ((5 + x)^{x})

(2 x e^{x} - y^{2}) d x + 2 y d y = 0

What is the d/(dt)((arccos(t))^2) ?
The d/(dt)((arccos(t))^2) is -(2arccos(t))/(sqrt(1-t^2))
What is the first d/(dt)((arccos(t))^2) ?
The first d/(dt)((arccos(t))^2) is -(2arccos(t))/(sqrt(1-t^2))