What is the derivative of (x^2-4)^2 ?

The derivative of (x^2-4)^2 is 4x(x^2-4)

What is the first derivative of (x^2-4)^2 ?

The first derivative of (x^2-4)^2 is 4x(x^2-4)

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derivative of

(x^{2} - 4)^{2}

4 x (x^{2} - 4)

Solution steps

\frac{d}{d x} ((x^{2} - 4)^{2})

Apply the chain rule:

2 (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

= 2 (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= 2 (x^{2} - 4) \cdot 2 x

Simplify

= 4 x (x^{2} - 4)

\int \frac{9 x ^{3} - x ^{2} + 45 x + 5}{x ^{3} + 5 x} d x

x \to 2 lim (x^{4} - 16)

\int 5 t e^{t} d t

x \to 6 - lim (\frac{x + 1}{x - 6})

\frac{d}{d x} (\frac{4 x ^{2} - 3}{x + 4})

What is the derivative of (x^2-4)^2 ?
The derivative of (x^2-4)^2 is 4x(x^2-4)
What is the first derivative of (x^2-4)^2 ?
The first derivative of (x^2-4)^2 is 4x(x^2-4)