What is the integral of (11x^{10}-(10)/(x^{10)}) ?

The integral of (11x^{10}-(10)/(x^{10)}) is x^{11}+(10)/(9x^9)+C

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integral of (11x^{10}-(10)/(x^{10)})

\int (11 x^{10} - \frac{10}{x ^{10}}) d x

x^{11} + \frac{10}{9 x ^{9}} + C

Solution steps

\int 11 x^{10} - \frac{10}{x ^{10}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 11 x^{10} d x - \int \frac{10}{x ^{10}} d x

\int 11 x^{10} d x = x^{11}

\int \frac{10}{x ^{10}} d x = - \frac{10}{9 x ^{9}}

= x^{11} - (- \frac{10}{9 x ^{9}})

Simplify

= x^{11} + \frac{10}{9 x ^{9}}

Add a constant to the solution

= x^{11} + \frac{10}{9 x ^{9}} + C

\frac{d}{d x} (3 x^{2} + 5 x - 1)

\frac{d}{d x} (\frac{5 x ^{2} - x + 1}{x ^{3} + 4 x ^{2}})

\int_{0}^{1} (x - x^{2}) d x

\frac{\partial}{\partial x} (x^{9} y^{9} + 5 x^{8} y)

y^{^{''}} - y - 4 = 0

What is the integral of (11x^{10}-(10)/(x^{10)}) ?
The integral of (11x^{10}-(10)/(x^{10)}) is x^{11}+(10)/(9x^9)+C