What is the derivative of (x^3/3-x) ?

The derivative of (x^3/3-x) is x^2-1

What is the first derivative of (x^3/3-x) ?

The first derivative of (x^3/3-x) is x^2-1

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\frac{d}{d x} (\frac{x ^{3}}{3} - x)

x^{2} - 1

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d x}{d x}

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d x}{d x} = 1

= x^{2} - 1

n = 2 \sum \infty - (\frac{2}{3})^{n}

x \to 0 + lim (\frac{ln ( 1 + 2 x )}{x})

\frac{d}{d x} (\frac{x + y}{2 + cos ( x )})

2 t^{2} - e^{- t}

x \to \frac{π}{2} lim (cos^{2} (x))

What is the derivative of (x^3/3-x) ?
The derivative of (x^3/3-x) is x^2-1
What is the first derivative of (x^3/3-x) ?
The first derivative of (x^3/3-x) is x^2-1