What is the tangent of y=tan(x),\at x=pi ?

The tangent of y=tan(x),\at x=pi is y=x-pi

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tangent of y=tan(x),\at x=pi

tangent of

y = tan (x), at x = π

y = x - π

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

y = tan (x) : \frac{d y}{d x} = sec^{2} (x)

Compute the slope of

y = tan (x)

x = π : m = 1

Find the line with slope m=

1

and passing through

(π, 0) : y = x - π

y = x - π

\int x^{4} (5 - x^{2}) d x

\frac{\partial}{\partial y} (- \frac{x}{( x + y ) ^{2}})

\frac{d}{d x} (\frac{x}{2 + c x})

\int \frac{1 - x ^{2}}{x ^{2}} d x

\int \frac{2}{( x - 3 ) ( x + 1 )} d x

What is the tangent of y=tan(x),\at x=pi ?
The tangent of y=tan(x),\at x=pi is y=x-pi