What is inverse oflaplace (12)/(3s-5) ?

The answer to inverse oflaplace (12)/(3s-5) is 4e^{(5t)/3}

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inverse oflaplace (12)/(3s-5)

inverse laplace

\frac{12}{3 s - 5}

4 e^{\frac{5 t}{3}}

Solution steps

L^{- 1} {\frac{12}{3 s - 5}}

= L^{- 1} {4 \cdot \frac{1}{s - \frac{5}{3}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s - \frac{5}{3}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - \frac{5}{3}}} = e^{\frac{5 t}{3}}

= 4 e^{\frac{5 t}{3}}

\frac{d ^{2}}{d x ^{2}} (\frac{6 π ^{2}}{6 - x})

n = 5 \sum \infty \frac{8 ^{n}}{9 ^{n}}

\int \frac{3}{5} - \frac{4}{x} d x

n = 1 \sum \infty n (sin (\frac{1}{n}))

\int (4 t^{2} - 3)^{2} d t

What is inverse oflaplace (12)/(3s-5) ?
The answer to inverse oflaplace (12)/(3s-5) is 4e^{(5t)/3}