What is the tangent of o2x2-3x+2 ?

The tangent of o2x2-3x+2 is x= 1/(2(-a_{0)+1)^2}o+(1-2a_{0})/(2(-a_{0)+1)}

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tangent of o2x2-3x+2

tangent of

o 2 x 2 - 3 x + 2

x = \frac{1}{2 ( - a _{0} + 1 ) ^{2}} o + \frac{1 - 2 a _{0}}{2 ( - a _{0} + 1 )}

Solution steps

Compute the tangent line to the general point

o = a_{0}

Find the tangent point:

(a_{0}, \frac{1}{2 ( - a _{0} + 1 )})

Find the slope of

x = o 2 x 2 - 3 x + 2 : \frac{d x}{d o} = \frac{1}{2 ( - o + 1 ) ^{2}}

Compute the slope of

x = o 2 x 2 - 3 x + 2

o = a_{0} : m = \frac{1}{2 ( - a _{0} + 1 ) ^{2}}

Find the line with slope m=

\frac{1}{2 ( - a _{0} + 1 ) ^{2}}

and passing through

(a_{0}, \frac{1}{2 ( - a _{0} + 1 )}) : x = \frac{1}{2 ( - a _{0} + 1 ) ^{2}} o + \frac{1 - 2 a _{0}}{2 ( - a _{0} + 1 )}

x = \frac{1}{2 ( - a _{0} + 1 ) ^{2}} o + \frac{1 - 2 a _{0}}{2 ( - a _{0} + 1 )}

\frac{\partial}{\partial y} (2 yz)

\int \frac{x ^{2} + 2 x - 3}{x + 1} d x

\int \frac{6}{6 x - 5} d x

\int t^{3} e^{t} d t

What is the tangent of o2x2-3x+2 ?
The tangent of o2x2-3x+2 is x= 1/(2(-a_{0)+1)^2}o+(1-2a_{0})/(2(-a_{0)+1)}