What is the derivative of sqrt(x+4y)+sqrt(2xy) ?

The derivative of sqrt(x+4y)+sqrt(2xy) is 1/(2sqrt(x+4y))+1/(2sqrt(2xy))*2y

What is the first derivative of sqrt(x+4y)+sqrt(2xy) ?

The first derivative of sqrt(x+4y)+sqrt(2xy) is 1/(2sqrt(x+4y))+1/(2sqrt(2xy))*2y

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derivative of

x + 4 y + 2 x y

\frac{1}{2 x + 4 y} + \frac{1}{2 2 x y} \cdot 2 y

Solution steps

\frac{d}{d x} (x + 4 y + 2 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x + 4 y) + \frac{d}{d x} (2 x y)

\frac{d}{d x} (x + 4 y) = \frac{1}{2 x + 4 y}

\frac{d}{d x} (2 x y) = \frac{1}{2 2 x y} \cdot 2 y

= \frac{1}{2 x + 4 y} + \frac{1}{2 2 x y} \cdot 2 y

\int 4 x + 10 d x

y^{^{'}} - 4 y = - 3 e^{3 t}, y (0) = 9

\int - \frac{1}{2} e^{- 3 x} d x

x \to 0 lim (\frac{- cos ( x )}{x})

\int - x + 6 d x

What is the derivative of sqrt(x+4y)+sqrt(2xy) ?
The derivative of sqrt(x+4y)+sqrt(2xy) is 1/(2sqrt(x+4y))+1/(2sqrt(2xy))*2y
What is the first derivative of sqrt(x+4y)+sqrt(2xy) ?
The first derivative of sqrt(x+4y)+sqrt(2xy) is 1/(2sqrt(x+4y))+1/(2sqrt(2xy))*2y