What is (\partial)/(\partial y)(100e^{-x-2y}) ?

The answer to (\partial)/(\partial y)(100e^{-x-2y}) is -200e^{-x-2y}

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(\partial)/(\partial y)(100e^{-x-2y})

\frac{\partial}{\partial y} (100 e^{- x - 2 y})

- 200 e^{- x - 2 y}

Solution steps

\frac{\partial}{\partial y} (100 e^{- x - 2 y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 100 \frac{\partial}{\partial y} (e^{- x - 2 y})

Apply the chain rule:

e^{- x - 2 y} \frac{\partial}{\partial y} (- x - 2 y)

= e^{- x - 2 y} \frac{\partial}{\partial y} (- x - 2 y)

\frac{\partial}{\partial y} (- x - 2 y) = - 2

= 100 e^{- x - 2 y} (- 2)

Simplify

= - 200 e^{- x - 2 y}

\int \frac{( - 1 ) ^{n} x ^{2 n}}{n !} d x

\int x e^{x^{2}} d x

\int \frac{2 x ^{2} - 5 x - 2}{( x - 2 ) ^{2} ( x - 1 )} d x

f (x) = 5 x + 30, at x = - 1

x \to - 1 + lim (∣ x ∣ - 3)

What is (\partial)/(\partial y)(100e^{-x-2y}) ?
The answer to (\partial)/(\partial y)(100e^{-x-2y}) is -200e^{-x-2y}