What is the integral from-1 to 1 of (x^{100}) ?

The integral from-1 to 1 of (x^{100}) is 2/101

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integral from-1 to 1 of (x^{100})

\int_{- 1}^{1} (x^{100}) d x

\frac{2}{101}

Decimal Notation

0.01980 \dots

Solution steps

\int_{- 1}^{1} x^{100} d x

Apply the Power Rule

: [\frac{x ^{101}}{101}]_{- 1}^{1}

= [\frac{x ^{101}}{101}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{101}

= \frac{2}{101}

\frac{d}{d x} (3 x^{2})

\frac{\partial}{\partial x} (\frac{x y}{x ^{2} + z ^{2}})

\frac{d}{d x} (\frac{- 8 x + 2}{3 x + 5})

x \to - 13 lim (- 12)

f (x) = \frac{x ^{3} + 2}{3}

What is the integral from-1 to 1 of (x^{100}) ?
The integral from-1 to 1 of (x^{100}) is 2/101