What is the integral from 0 to 1 of x^2x ?

The integral from 0 to 1 of x^2x is 1/4

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integral from 0 to 1 of x^2x

\int_{0}^{1} x^{2} x d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{0}^{1} x^{2} x d x

Simplify

x^{2} x : x^{3}

= \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

\frac{x}{x ^{2} - 7}

\int (x^{4} - x^{2} + \frac{1}{x ^{3}} - \frac{1}{x ^{2}}) d x

\int 3 + 2 x y d x

y = - 2 x - 4

\frac{d}{d x} (\frac{A x + B}{4 - x})

What is the integral from 0 to 1 of x^2x ?
The integral from 0 to 1 of x^2x is 1/4