What is the integral from 0 to 4pi of sqrt(1/2) ?

The integral from 0 to 4pi of sqrt(1/2) is 2sqrt(2)pi

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integral from 0 to 4pi of sqrt(1/2)

\int_{0}^{4 π} \frac{1}{2}

22 π

Decimal Notation

8.88576 \dots

Solution steps

\int_{0}^{4 π} \frac{1}{2} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{2} x]_{0}^{4 π}

Compute the boundaries:

22 π

= 22 π

n = 1 \sum \infty \frac{n ^{2}}{6 ^{n}}

y = 7 x e^{x}, (0, 0)

y = \frac{1}{t ( 8 t + 1 )}

2 x^{2}, 5 x - 3 x^{2}

y^{^{'}} = (1 - 7 x) y^{2}

What is the integral from 0 to 4pi of sqrt(1/2) ?
The integral from 0 to 4pi of sqrt(1/2) is 2sqrt(2)pi