What is the integral of x^2cos(1/7 x) ?

The integral of x^2cos(1/7 x) is 7x^2sin(1/7 x)-14(-7xcos(1/7 x)+49sin(1/7 x))+C

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integral of x^2cos(1/7 x)

\int x^{2} cos (\frac{1}{7} x) d x

7 x^{2} sin (\frac{1}{7} x) - 14 (- 7 x cos (\frac{1}{7} x) + 49 sin (\frac{1}{7} x)) + C

Solution steps

\int x^{2} cos (\frac{1}{7} x) d x

Apply Integration By Parts

: 7 x^{2} sin (\frac{1}{7} x) - \int 14 x sin (\frac{1}{7} x) d x

= 7 x^{2} sin (\frac{1}{7} x) - \int 14 x sin (\frac{1}{7} x) d x

\int 14 x sin (\frac{1}{7} x) d x = 14 (- 7 x cos (\frac{1}{7} x) + 49 sin (\frac{1}{7} x))

= 7 x^{2} sin (\frac{1}{7} x) - 14 (- 7 x cos (\frac{1}{7} x) + 49 sin (\frac{1}{7} x))

Add a constant to the solution

= 7 x^{2} sin (\frac{1}{7} x) - 14 (- 7 x cos (\frac{1}{7} x) + 49 sin (\frac{1}{7} x)) + C

y^{^{''}} - 4 y^{^{'}} = 7 - 3 e^{4 x}

x \to - π - lim ((x + π) csc (x))

ln^{5} (x)

\int \frac{2 x}{4 x ^{2} + 1} d x

\int \frac{1}{( 1 + y ^{2} )} d y

What is the integral of x^2cos(1/7 x) ?
The integral of x^2cos(1/7 x) is 7x^2sin(1/7 x)-14(-7xcos(1/7 x)+49sin(1/7 x))+C