What is the tangent of-3cos(x),\at x=-pi/3 ?

The tangent of-3cos(x),\at x=-pi/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2

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tangent of-3cos(x),\at x=-pi/3

tangent of

- 3 cos (x), at x = - \frac{π}{3}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

Solution steps

Find the tangent point:

(- \frac{π}{3}, - \frac{3}{2})

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

Compute the slope of

y = - 3 cos (x)

x = - \frac{π}{3} : m = - \frac{3 3}{2}

Find the line with slope m=

- \frac{3 3}{2}

and passing through

(- \frac{π}{3}, - \frac{3}{2}) : y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

e^{2 x^{3}}

\frac{\partial}{\partial y} (4 x^{3} y^{2} - 1)

(y p + 2 y) (p d y + y d p) - (2 y p + 4 y) d y = 0

cos^{2} (13 t)

y = ln (5)

What is the tangent of-3cos(x),\at x=-pi/3 ?
The tangent of-3cos(x),\at x=-pi/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2