What is the derivative of y=sqrt(3-6x) ?

The derivative of y=sqrt(3-6x) is -3/(sqrt(3-6x))

What is the first derivative of y=sqrt(3-6x) ?

The first derivative of y=sqrt(3-6x) is -3/(sqrt(3-6x))

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derivative of

y = 3 - 6 x

- \frac{3}{3 - 6 x}

Solution steps

\frac{d}{d x} (3 - 6 x)

Apply the chain rule:

\frac{1}{2 3 - 6 x} \frac{d}{d x} (3 - 6 x)

= \frac{1}{2 3 - 6 x} \frac{d}{d x} (3 - 6 x)

\frac{d}{d x} (3 - 6 x) = - 6

= \frac{1}{2 3 - 6 x} (- 6)

Simplify

\frac{1}{2 3 - 6 x} (- 6) : - \frac{3}{3 - 6 x}

= - \frac{3}{3 - 6 x}

\frac{\partial}{\partial x} (x^{2} cos (x))

y^{^{'}} + x y = 1

\int 1 + 2 sin (x) + sin^{2} (x) d x

\int 2^{x} tan (3 - 2^{x}) d x

2 x y \frac{d y}{d x} = 5

What is the derivative of y=sqrt(3-6x) ?
The derivative of y=sqrt(3-6x) is -3/(sqrt(3-6x))
What is the first derivative of y=sqrt(3-6x) ?
The first derivative of y=sqrt(3-6x) is -3/(sqrt(3-6x))