What is the solution for y^'+xy^2=x ?

The solution for y^'+xy^2=x is y=(e^{c_{1}})/(e^{x^2)-e^{c_{1}}}+(e^{x^2})/(e^{x^2)-e^{c_{1}}}

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y^'+xy^2=x

y^{^{'}} + x y^{2} = x

y = \frac{e ^{c_{1}}}{e ^{x^{2}} - e ^{c_{1}}} + \frac{e ^{x^{2}}}{e ^{x^{2}} - e ^{c_{1}}}

Solution steps

y^{'} (x) + x y^{2} = x

Solve Bernoulli ODE:

y = \frac{e ^{c_{1}}}{e ^{x^{2}} - e ^{c_{1}}} + \frac{e ^{x^{2}}}{e ^{x^{2}} - e ^{c_{1}}}

y = \frac{e ^{c_{1}}}{e ^{x^{2}} - e ^{c_{1}}} + \frac{e ^{x^{2}}}{e ^{x^{2}} - e ^{c_{1}}}

x \to 0 - lim (e^{(\frac{1}{x})})

\frac{4}{4 s ^{2} + 1}

\int \frac{1}{4} e^{4 x} d x

\int \frac{13}{x ^{3} - 27} d x

\frac{d}{d x} (- \frac{1}{3} x^{- 3})

What is the solution for y^'+xy^2=x ?
The solution for y^'+xy^2=x is y=(e^{c_{1}})/(e^{x^2)-e^{c_{1}}}+(e^{x^2})/(e^{x^2)-e^{c_{1}}}