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Popular >

y^'+5y=8,y(0)=0

Solution

y^{^{'}} + 5 y = 8, y (0) = 0

Solution

y = - \frac{8 e ^{- 5 t}}{5} + \frac{8}{5}

Solution steps

y^{'} (t) + 5 y = 8

Solve separable ODE:

y = - \frac{8 e ^{- 5 t}}{5} + \frac{8}{5}

y = - \frac{8 e ^{- 5 t}}{5} + \frac{8}{5}

Graph

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x^{''}-8x^'+17x=0

x^{^{''}} - 8 x^{^{'}} + 17 x = 0

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\frac{d}{d x} (e^{\frac{x}{( x - 6 )}})

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Frequently Asked Questions (FAQ)

What is the solution for y^'+5y=8,y(0)=0 ?
The solution for y^'+5y=8,y(0)=0 is y=-(8e^{-5t})/5+8/5