What is the derivative of 8/(9x^9) ?

The derivative of 8/(9x^9) is -8/(x^{10)}

What is the first derivative of 8/(9x^9) ?

The first derivative of 8/(9x^9) is -8/(x^{10)}

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derivative of

\frac{8}{9 x ^{9}}

- \frac{8}{x ^{10}}

Solution steps

\frac{d}{d x} (\frac{8}{9 x ^{9}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{8}{9} \frac{d}{d x} (\frac{1}{x ^{9}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{8}{9} \frac{d}{d x} (x^{- 9})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{8}{9} (- 9 x^{- 9 - 1})

Simplify

\frac{8}{9} (- 9 x^{- 9 - 1}) : - \frac{8}{x ^{10}}

= - \frac{8}{x ^{10}}

- sin (x) - 2 sec^{2} (x) tan (x)

\int \frac{1}{7 x ^{5}} d x

y^{^{'}} + 2 x y = x e^{- x^{2}}, y (0) = 1

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\int (4 x - 7) d x

What is the derivative of 8/(9x^9) ?
The derivative of 8/(9x^9) is -8/(x^{10)}
What is the first derivative of 8/(9x^9) ?
The first derivative of 8/(9x^9) is -8/(x^{10)}