What is the tangent of f(x)= 1/(x^3),(-3,-1/27) ?

The tangent of f(x)= 1/(x^3),(-3,-1/27) is y=-1/27 x-4/27

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tangent of f(x)= 1/(x^3),(-3,-1/27)

tangent of

f (x) = \frac{1}{x ^{3}}, (- 3, - \frac{1}{27})

y = - \frac{1}{27} x - \frac{4}{27}

Solution steps

Find the slope of

f (x) = \frac{1}{x ^{3}} : \frac{df ( x )}{d x} = - \frac{3}{x ^{4}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{27}

Find the line with slope m=

- \frac{1}{27}

and passing through

(- 3, - \frac{1}{27}) : y = - \frac{1}{27} x - \frac{4}{27}

y = - \frac{1}{27} x - \frac{4}{27}

\int \frac{t ^{2}}{( t ^{3} - 2 ) ^{5}} d t

\frac{d}{d x} (x^{0.85})

n = 1 \sum \infty (1 - \frac{1}{3 n})^{n}

x \to - 3 lim (\frac{x ^{2} - 6}{3 - x})

y^{^{''}} - 6 y^{^{'}} + 36 y = 0

What is the tangent of f(x)= 1/(x^3),(-3,-1/27) ?
The tangent of f(x)= 1/(x^3),(-3,-1/27) is y=-1/27 x-4/27