What is the derivative of 2x^2-8x+5 ?

The derivative of 2x^2-8x+5 is 4x-8

What is the first derivative of 2x^2-8x+5 ?

The first derivative of 2x^2-8x+5 is 4x-8

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\frac{d}{d x} (2 x^{2} - 8 x + 5)

4 x - 8

Solution steps

\frac{d}{d x} (2 x^{2} - 8 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5) = 0

= 4 x - 8 + 0

Simplify

= 4 x - 8

\frac{d}{d x} (\frac{3 x}{π})

b \to 1 lim (ln (ln (b)))

f (x) = \frac{5}{3 x}, at x = 1

\frac{d}{d x} (2 - x^{3})

\int \frac{x ^{3} + 9}{x ^{2} + 9} d x

What is the derivative of 2x^2-8x+5 ?
The derivative of 2x^2-8x+5 is 4x-8
What is the first derivative of 2x^2-8x+5 ?
The first derivative of 2x^2-8x+5 is 4x-8