What is the first derivative of 2x-1 ?

The first derivative of 2x-1 is 2

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derivative of 2x-1

derivative of

2 x - 1

2

Solution steps

\frac{d}{d x} (2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 - 0

Simplify

= 2

\int \frac{1}{x ^{2} - 6 x + 13} d x

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = - 4, y^{^{'}} (0) = 2

\frac{\partial}{\partial x} (x^{2} \cdot y)

\int x e^{(2 x)} d x

\int_{0}^{5} \frac{3 x}{( x - 6 ) ^{2}} d x