What is the tangent of f(x)=-3x^4 ?

The tangent of f(x)=-3x^4 is y=-12a_{0}^3x+9a_{0}^4

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tangent of f(x)=-3x^4

tangent of

f (x) = - 3 x^{4}

y = - 12 a_{0}^{3} x + 9 a_{0}^{4}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 a_{0}^{4})

Find the slope of

f (x) = - 3 x^{4} : \frac{df ( x )}{d x} = - 12 x^{3}

Compute the slope of

f (x) = - 3 x^{4}

x = a_{0} : m = - 12 a_{0}^{3}

Find the line with slope m=

- 12 a_{0}^{3}

and passing through

(a_{0}, - 3 a_{0}^{4}) : y = - 12 a_{0}^{3} x + 9 a_{0}^{4}

y = - 12 a_{0}^{3} x + 9 a_{0}^{4}

\int_{0}^{π} 9 sin^{4} (x) d x

y = (cos (7 x))^{x}

\frac{x + 6}{5}, ∣ x ∣

40 ln (3 x + 1)

\frac{1}{2} (e^{x} + e^{- x})

What is the tangent of f(x)=-3x^4 ?
The tangent of f(x)=-3x^4 is y=-12a_{0}^3x+9a_{0}^4