What is the derivative of f(x)=x^{-1}-x ?

The derivative of f(x)=x^{-1}-x is -1/(x^2)-1

What is the first derivative of f(x)=x^{-1}-x ?

The first derivative of f(x)=x^{-1}-x is -1/(x^2)-1

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derivative of

f (x) = x^{- 1} - x

- \frac{1}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (x^{- 1} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{- 1}) - \frac{d x}{d x}

\frac{d}{d x} (x^{- 1}) = - \frac{1}{x ^{2}}

\frac{d x}{d x} = 1

= - \frac{1}{x ^{2}} - 1

\int t - sin (t) d t

\frac{d}{d x} ((e^{- x}) d x)

\frac{d}{d x} (- e^{- 1})

x \to 4 lim (\frac{3}{4 - x})

\int_{- 2}^{3} \frac{7}{x ^{4}} d x

What is the derivative of f(x)=x^{-1}-x ?
The derivative of f(x)=x^{-1}-x is -1/(x^2)-1
What is the first derivative of f(x)=x^{-1}-x ?
The first derivative of f(x)=x^{-1}-x is -1/(x^2)-1