What is the integral from-9 to 0 of sqrt(y+9) ?

The integral from-9 to 0 of sqrt(y+9) is 18

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integral from-9 to 0 of sqrt(y+9)

\int_{- 9}^{0} y + 9 d y

18

Solution steps

\int_{- 9}^{0} y + 9 d y

Apply u-substitution

: \int_{0}^{9} u d u

= \int_{0}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{9}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{9}

Compute the boundaries:

18

= 18

x \to 3 lim (x^{2} + 8 x - 2)

n = 5 \sum \infty \frac{2}{n ^{2} - 1}

\int \frac{x}{5 x - 2} d x

\int_{\frac{1}{3}}^{7} 6 x ln (3 x) d x

\frac{d}{d x} (\frac{4 x ^{3} + 2 x + 5}{x})

What is the integral from-9 to 0 of sqrt(y+9) ?
The integral from-9 to 0 of sqrt(y+9) is 18