What is the solution for y^'sin(y)=x^4 ?

The solution for y^'sin(y)=x^4 is y=arccos(-(x^5+c_{1})/5)+2pin,y=-arccos(-(x^5+c_{1})/5)+2pin

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y^'sin(y)=x^4

y^{^{'}} sin (y) = x^{4}

y = arccos (- \frac{x ^{5} + c _{1}}{5}) + 2 πn, y = - arccos (- \frac{x ^{5} + c _{1}}{5}) + 2 πn

Solution steps

y^{'} (x) sin (y) = x^{4}

Solve separable ODE:

y = arccos (- \frac{x ^{5} + c _{1}}{5}) + 2 πn, y = - arccos (- \frac{x ^{5} + c _{1}}{5}) + 2 πn

y = arccos (- \frac{x ^{5} + c _{1}}{5}) + 2 πn, y = - arccos (- \frac{x ^{5} + c _{1}}{5}) + 2 πn

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What is the solution for y^'sin(y)=x^4 ?
The solution for y^'sin(y)=x^4 is y=arccos(-(x^5+c_{1})/5)+2pin,y=-arccos(-(x^5+c_{1})/5)+2pin