What is the derivative of (1+p^2)(x+e^{-x})-10 ?

The derivative of (1+p^2)(x+e^{-x})-10 is 2p(x+e^{-x})

What is the first derivative of (1+p^2)(x+e^{-x})-10 ?

The first derivative of (1+p^2)(x+e^{-x})-10 is 2p(x+e^{-x})

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derivative of

(1 + p^{2}) (x + e^{- x}) - 10

2 p (x + e^{- x})

Solution steps

\frac{d}{d p} ((1 + p^{2}) (x + e^{- x}) - 10)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d p} ((1 + p^{2}) (x + e^{- x})) - \frac{d}{d p} (10)

\frac{d}{d p} ((1 + p^{2}) (x + e^{- x})) = 2 p (x + e^{- x})

\frac{d}{d p} (10) = 0

= 2 p (x + e^{- x}) - 0

Simplify

= 2 p (x + e^{- x})

\int e^{x} sin^{2} (e^{x}) d x

y = x^{2}, y = x + 2, - 2, 2

x \to 3 + lim (\frac{x - 3}{∣ x - 3 ∣})

f (x) = 4 x^{3} (2 x^{2} - 3 x^{3})

What is the derivative of (1+p^2)(x+e^{-x})-10 ?
The derivative of (1+p^2)(x+e^{-x})-10 is 2p(x+e^{-x})
What is the first derivative of (1+p^2)(x+e^{-x})-10 ?
The first derivative of (1+p^2)(x+e^{-x})-10 is 2p(x+e^{-x})