What is the tangent of y= 1/(x^6),(-3, 1/729) ?

The tangent of y= 1/(x^6),(-3, 1/729) is y= 2/729 x+7/729

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tangent of y= 1/(x^6),(-3, 1/729)

tangent of

y = \frac{1}{x ^{6}}, (- 3, \frac{1}{729})

y = \frac{2}{729} x + \frac{7}{729}

Solution steps

Find the slope of

y = \frac{1}{x ^{6}} : \frac{d y}{d x} = - \frac{6}{x ^{7}}

Compute the slope of

y = \frac{1}{x ^{6}}

(- 3, \frac{1}{729}) : m = \frac{2}{729}

Find the line with slope m=

\frac{2}{729}

and passing through

(- 3, \frac{1}{729}) : y = \frac{2}{729} x + \frac{7}{729}

y = \frac{2}{729} x + \frac{7}{729}

\int x e^{- 9 x^{2}} d x

y^{^{'}} + e^{x + y} = 0

t \to 0 lim (sin (8 t))

\frac{x y d y}{d x} + y^{2} = 2 x

sin (e^{4 x})

What is the tangent of y= 1/(x^6),(-3, 1/729) ?
The tangent of y= 1/(x^6),(-3, 1/729) is y= 2/729 x+7/729