What is area y=e^x,y=x,x=0,x=2 ?

The answer to area y=e^x,y=x,x=0,x=2 is e^2-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=e^x,y=x,x=0,x=2

area

y = e^{x}, y = x, x = 0, x = 2

e^{2} - 3

Decimal Notation

4.38905 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} ∣ e^{x} - x ∣ d x

Solve

\int_{0}^{2} ∣ e^{x} - x ∣ d x : e^{2} - 3

The area is:

= e^{2} - 3

\int \frac{( x ^{2} + 1 )}{( x - 5 ) ( x - 4 ) ^{2}} d x

\frac{d}{d x} (- \frac{1}{2 ( 1 + x ) ^{\frac{3}{2}}})

f (x) = - \frac{6}{( 1 + 3 x ) ^{2}}

\frac{d}{d x} (ln (\frac{( 2 )}{3 - x ^{2}}))