What is the tangent of y=x^3-3x+5,(3,23) ?

The tangent of y=x^3-3x+5,(3,23) is y=24x-49

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^3-3x+5,(3,23)

tangent of

y = x^{3} - 3 x + 5, (3, 23)

y = 24 x - 49

Solution steps

Find the slope of

y = x^{3} - 3 x + 5 : \frac{d y}{d x} = 3 x^{2} - 3

Compute the slope of

y = x^{3} - 3 x + 5

(3, 23) : m = 24

Find the line with slope m=

24

and passing through

(3, 23) : y = 24 x - 49

y = 24 x - 49

f (x) = \frac{x}{x ^{2} + 1}, at x = 0

\int \frac{1}{1 - v} d v

\frac{1}{s ( s + \frac{1}{15} )}

n = 1 \sum \infty \frac{( e ^{n} )}{n !}

\int sin (x - 1) d x

What is the tangent of y=x^3-3x+5,(3,23) ?
The tangent of y=x^3-3x+5,(3,23) is y=24x-49