What is the solution for 9xy^'-2y=-(x^2)/(y^8) ?

The solution for 9xy^'-2y=-(x^2)/(y^8) is y=\sqrt[9]{-ln(x)x^2+c_{1}x^2}

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9xy^'-2y=-(x^2)/(y^8)

9 x y^{^{'}} - 2 y = - \frac{x ^{2}}{y ^{8}}

Solution steps

9 x y^{'} (x) - 2 y = - \frac{x ^{2}}{y ^{8}}

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What is the solution for 9xy^'-2y=-(x^2)/(y^8) ?
The solution for 9xy^'-2y=-(x^2)/(y^8) is y=\sqrt[9]{-ln(x)x^2+c_{1}x^2}