What is the derivative of (-9/(x^2)) ?

The derivative of (-9/(x^2)) is (18)/(x^3)

What is the first derivative of (-9/(x^2)) ?

The first derivative of (-9/(x^2)) is (18)/(x^3)

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\frac{d}{d x} (\frac{- 9}{x ^{2}})

\frac{18}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 9}{x ^{2}})

Simplify

\frac{- 9}{x ^{2}} : - \frac{9}{x ^{2}}

= \frac{d}{d x} (- \frac{9}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 9 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 9 (- 2 x^{- 2 - 1})

Simplify

- 9 (- 2 x^{- 2 - 1}) : \frac{18}{x ^{3}}

= \frac{18}{x ^{3}}

\int e^{- 2 t} d t

y^{^{'}} - \frac{8}{x} y = \frac{y ^{4}}{x ^{17}}, y (1) = 1

x \to 3 + lim (- \frac{2}{x ^{2} - 9})

\int 5 e^{- 0.4 x} d x

f (x) = 7 sec (x), at x = \frac{π}{6}

What is the derivative of (-9/(x^2)) ?
The derivative of (-9/(x^2)) is (18)/(x^3)
What is the first derivative of (-9/(x^2)) ?
The first derivative of (-9/(x^2)) is (18)/(x^3)