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Popular >

integral from 1 to 2 of (4x^3-6x)

Solution

\int_{1}^{2} (4 x^{3} - 6 x) d x

Solution

6

Solution steps

\int_{1}^{2} 4 x^{3} - 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 4 x^{3} d x - \int_{1}^{2} 6 x d x

\int_{1}^{2} 4 x^{3} d x = 15

\int_{1}^{2} 6 x d x = 9

= 15 - 9

Simplify

= 6

Popular Examples

integral from 0 to x of (2x-y)

\int_{0}^{x} (2 x - y) d y

integral of (1+3x)^2

\int (1 + 3 x)^{2} d x

sum from n=1 to infinity of arctan(15n)

n = 1 \sum \infty arctan (15 n)

tangent of f(x)=6x^2+6,\at x=-2 tangent of

f (x) = 6 x^{2} + 6, at x = - 2

derivative of (3x-1)(x-2)^4 derivative of

(3 x - 1) (x - 2)^{4}

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (4x^3-6x) ?
The integral from 1 to 2 of (4x^3-6x) is 6