What is the derivative of (2x^2+7^5) ?

The derivative of (2x^2+7^5) is 20x(2x^2+7)^4

What is the first derivative of (2x^2+7^5) ?

The first derivative of (2x^2+7^5) is 20x(2x^2+7)^4

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\frac{d}{d x} ((2 x^{2} + 7)^{5})

20 x (2 x^{2} + 7)^{4}

Solution steps

\frac{d}{d x} ((2 x^{2} + 7)^{5})

Apply the chain rule:

5 (2 x^{2} + 7)^{4} \frac{d}{d x} (2 x^{2} + 7)

= 5 (2 x^{2} + 7)^{4} \frac{d}{d x} (2 x^{2} + 7)

\frac{d}{d x} (2 x^{2} + 7) = 4 x

= 5 (2 x^{2} + 7)^{4} \cdot 4 x

Simplify

= 20 x (2 x^{2} + 7)^{4}

\frac{\partial}{\partial x} (ln (e^{x} + x y^{3}))

\frac{d}{d s} (ln (1 + \frac{1}{s ^{2}}))

\int (2^{x} + x)^{2} d x

\int cos (\frac{π x}{2}) d x

\frac{d y}{d x} = 16 x sec^{2} (4 x)

What is the derivative of (2x^2+7^5) ?
The derivative of (2x^2+7^5) is 20x(2x^2+7)^4
What is the first derivative of (2x^2+7^5) ?
The first derivative of (2x^2+7^5) is 20x(2x^2+7)^4