What is the solution for (dy)/(dx)=((y^2+2xy))/(x^2) ?

The solution for (dy)/(dx)=((y^2+2xy))/(x^2) is y=(x^2)/(-x+c_{1)}

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(dy)/(dx)=((y^2+2xy))/(x^2)

\frac{d y}{d x} = \frac{( y ^{2} + 2 x y )}{x ^{2}}

y = \frac{x ^{2}}{- x + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{( y ^{2} + 2 x y )}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- x + c _{1}}

y = \frac{x ^{2}}{- x + c _{1}}

n = 1 \sum \infty 3 e^{- 5 n}

f (x) = 9 + 4 x^{2} - 2 x^{3}, at x = 2

f (x) = 1 + 4 + x^{2}, at x = 0

f (x) = 8 x^{2}

f (2)

What is the solution for (dy)/(dx)=((y^2+2xy))/(x^2) ?
The solution for (dy)/(dx)=((y^2+2xy))/(x^2) is y=(x^2)/(-x+c_{1)}