What is the solution for 2y(dy)/(dx)+2=y^2+2x ?

The solution for 2y(dy)/(dx)+2=y^2+2x is y=sqrt(-2x+c_{1)e^x},y=-sqrt(-2x+c_{1)e^x}

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2y(dy)/(dx)+2=y^2+2x

2 y \frac{d y}{d x} + 2 = y^{2} + 2 x

y = - 2 x + c_{1} e^{x}, y = - - 2 x + c_{1} e^{x}

Solution steps

2 y \frac{d y}{d x} + 2 = y^{2} + 2 x

Solve Bernoulli ODE:

y = - 2 x + c_{1} e^{x}, y = - - 2 x + c_{1} e^{x}

y = - 2 x + c_{1} e^{x}, y = - - 2 x + c_{1} e^{x}

\frac{d}{d x} ((2 x - 2)^{3} (3 x - 1)^{2})

x \to 0 + lim (\frac{1 - ln ( x )}{e ^{\frac{1}{x}}})

\frac{d}{d x} (2 x^{2} y - x^{3})

\frac{d}{d x} (\frac{3}{2 x + 5})

\frac{\partial}{\partial x} (y^{2} - x^{2})

What is the solution for 2y(dy)/(dx)+2=y^2+2x ?
The solution for 2y(dy)/(dx)+2=y^2+2x is y=sqrt(-2x+c_{1)e^x},y=-sqrt(-2x+c_{1)e^x}