What is the integral from 4 to infinity of 5e^{-y/2} ?

The integral from 4 to infinity of 5e^{-y/2} is (10)/(e^2)

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integral from 4 to infinity of 5e^{-y/2}

\int_{4}^{\infty} 5 e^{- \frac{y}{2}} d y

\frac{10}{e ^{2}}

Decimal Notation

1.35335 \dots

Solution steps

\int_{4}^{\infty} 5 e^{- \frac{y}{2}} d y

Compute the indefinite integral:

\int 5 e^{- \frac{y}{2}} d y = - 10 e^{- \frac{y}{2}} + C

Compute the boundaries:

\int_{4}^{\infty} 5 e^{- \frac{y}{2}} d y = 0 - (- \frac{10}{e ^{2}})

= 0 - (- \frac{10}{e ^{2}})

Simplify

= \frac{10}{e ^{2}}

\int \frac{x}{x + 2 y} d x

\frac{x ^{2} - 1}{x ^{3}}

\frac{d v}{d t} = 2.1 - \frac{7 v}{2180}, v (0) = 0

f (x) = - 2 x^{3}, at x = 2

\frac{d}{d z} (\frac{z ^{2}}{( z - 2 i ) ^{2}})

What is the integral from 4 to infinity of 5e^{-y/2} ?
The integral from 4 to infinity of 5e^{-y/2} is (10)/(e^2)