What is the derivative of (4-3x-x^2)/(x^2-6) ?

The derivative of (4-3x-x^2)/(x^2-6) is (3x^2+4x+18)/((x^2-6)^2)

What is the first derivative of (4-3x-x^2)/(x^2-6) ?

The first derivative of (4-3x-x^2)/(x^2-6) is (3x^2+4x+18)/((x^2-6)^2)

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derivative of

\frac{4 - 3 x - x ^{2}}{x ^{2} - 6}

\frac{3 x ^{2} + 4 x + 18}{( x ^{2} - 6 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 - 3 x - x ^{2}}{x ^{2} - 6})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 - 3 x - x ^{2} ) ( x ^{2} - 6 ) - \frac{d}{d x} ( x ^{2} - 6 ) ( 4 - 3 x - x ^{2} )}{( x ^{2} - 6 ) ^{2}}

\frac{d}{d x} (4 - 3 x - x^{2}) = - 2 x - 3

\frac{d}{d x} (x^{2} - 6) = 2 x

= \frac{( - 2 x - 3 ) ( x ^{2} - 6 ) - 2 x ( 4 - 3 x - x ^{2} )}{( x ^{2} - 6 ) ^{2}}

Expand

(- 2 x - 3) (x^{2} - 6) - 2 x (4 - 3 x - x^{2}) : 3 x^{2} + 4 x + 18

= \frac{3 x ^{2} + 4 x + 18}{( x ^{2} - 6 ) ^{2}}

\int_{0}^{\frac{π}{2}} - 2 sin^{2} (3 x) d x

(\frac{d y}{d x}) = 0.011 \cdot y \cdot (2 - (y - 25))

\int \frac{5}{( 3 x - 1 ) ^{7}} d x

\frac{d ^{2}}{d x ^{2}} (4 x cos (x^{2}))

\frac{4 s}{s ^{2} + 6 s + 9}

What is the derivative of (4-3x-x^2)/(x^2-6) ?
The derivative of (4-3x-x^2)/(x^2-6) is (3x^2+4x+18)/((x^2-6)^2)
What is the first derivative of (4-3x-x^2)/(x^2-6) ?
The first derivative of (4-3x-x^2)/(x^2-6) is (3x^2+4x+18)/((x^2-6)^2)