What is the integral of cos(x)*sin^2(x) ?

The integral of cos(x)*sin^2(x) is (sin^3(x))/3+C

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integral of cos(x)*sin^2(x)

\int cos (x) \cdot sin^{2} (x) d x

\frac{sin ^{3} ( x )}{3} + C

Solution steps

\int cos (x) sin^{2} (x) d x

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= \frac{sin ^{3} ( x )}{3}

Add a constant to the solution

= \frac{sin ^{3} ( x )}{3} + C

\int x^{\frac{5}{3}} d x

\int sec^{2} (8 x) d x

(y \cdot e^{- x}) \frac{d y}{d x} = x

\int_{0}^{π} 1 + cos (2 x) d x

\frac{\partial}{\partial x} (x + y^{2} + x y + 3)

What is the integral of cos(x)*sin^2(x) ?
The integral of cos(x)*sin^2(x) is (sin^3(x))/3+C