What is the derivative of (3x+4)^2 ?

The derivative of (3x+4)^2 is 6(3x+4)

What is the first derivative of (3x+4)^2 ?

The first derivative of (3x+4)^2 is 6(3x+4)

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derivative of

(3 x + 4)^{2}

6 (3 x + 4)

Solution steps

\frac{d}{d x} ((3 x + 4)^{2})

Apply the chain rule:

2 (3 x + 4) \frac{d}{d x} (3 x + 4)

= 2 (3 x + 4) \frac{d}{d x} (3 x + 4)

\frac{d}{d x} (3 x + 4) = 3

= 2 (3 x + 4) \cdot 3

Simplify

= 6 (3 x + 4)

\frac{d}{d t} (2 t - 1)

\frac{\partial}{\partial x} (- x e^{\frac{y}{x}})

t^{3} \frac{d y}{d t} + 3 t^{2} y = 9 cos (t), y (π) = 0

cos (10 t)

\frac{\partial}{\partial x} (e^{x} (x - y)^{2})

What is the derivative of (3x+4)^2 ?
The derivative of (3x+4)^2 is 6(3x+4)
What is the first derivative of (3x+4)^2 ?
The first derivative of (3x+4)^2 is 6(3x+4)