What is the solution for x(dy)/(dx)=yln(xy) ?

The solution for x(dy)/(dx)=yln(xy) is y=(e^{c_{1}x-1})/x

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x(dy)/(dx)=yln(xy)

x \frac{d y}{d x} = y ln (x y)

y = \frac{e ^{c_{1} x - 1}}{x}

Solution steps

x \frac{d y}{d x} = y ln (x y)

Solve using substitution:

y = \frac{e ^{c_{1} x - 1}}{x}

y = \frac{e ^{c_{1} x - 1}}{x}

\frac{\partial}{\partial x} (sin (y) e^{x})

n = 0 \sum \infty \frac{3 ^{n}}{n}

\int_{0}^{2} - 3 x^{3} x^{2} + 4 d x

\frac{16}{s ^{2} + 3 s + 16}

\int_{0}^{2} \frac{x}{x ^{2} + 1} d x

What is the solution for x(dy)/(dx)=yln(xy) ?
The solution for x(dy)/(dx)=yln(xy) is y=(e^{c_{1}x-1})/x