What is the solution for (y/2+2x)dx+(-1)dy=0 ?

The solution for (y/2+2x)dx+(-1)dy=0 is y=-4(x+2)+c_{1}e^{x/2}

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(y/2+2x)dx+(-1)dy=0

(\frac{y}{2} + 2 x) d x + (- 1) d y = 0

y = - 4 (x + 2) + c_{1} e^{\frac{x}{2}}

Solution steps

(\frac{y}{2} + 2 x) d x + (- 1) d y = 0

Solve linear ODE:

y = - 4 (x + 2) + c_{1} e^{\frac{x}{2}}

y = - 4 (x + 2) + c_{1} e^{\frac{x}{2}}

y = 3, y = x, x = 0

\frac{x d y}{d x} + x y = 1 - y

\frac{d y}{d x} = - 2 y

n = 2 \sum \infty n e^{- 3 n}

n \to \infty lim (2^{- n})

What is the solution for (y/2+2x)dx+(-1)dy=0 ?
The solution for (y/2+2x)dx+(-1)dy=0 is y=-4(x+2)+c_{1}e^{x/2}