en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+2y=16

Solution

y^{^{'}} + 2 y = 16

Solution

y = - e^{- 2 t - c_{1}} + 8

Solution steps

y^{'} (t) + 2 y = 16

Solve separable ODE:

y = - e^{- 2 t - c_{1}} + 8

y = - e^{- 2 t - c_{1}} + 8

Popular Examples

integral of x(x^2-1)^5

\int x (x^{2} - 1)^{5} d x

(d^2)/(dx^2)(e^x-x^5)

\frac{d ^{2}}{d x ^{2}} (e^{x} - x^{5})

integral of sqrt(1+((x^2)/4-1/(x^2))^2)

\int 1 + (\frac{x ^{2}}{4} - \frac{1}{x ^{2}})^{2} d x

y^{''}-4y^'=e^{2x}

y^{^{''}} - 4 y^{^{'}} = e^{2 x}

derivative of (h/2)^2 derivative of

(\frac{h}{2})^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=16 ?
The solution for y^'+2y=16 is y=-e^{-2t-c_{1}}+8