What is the integral of x^4-4x^2+4 ?

The integral of x^4-4x^2+4 is (x^5)/5-(4x^3)/3+4x+C

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integral of x^4-4x^2+4

\int x^{4} - 4 x^{2} + 4 d x

\frac{x ^{5}}{5} - \frac{4 x ^{3}}{3} + 4 x + C

Solution steps

\int x^{4} - 4 x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{4} d x - \int 4 x^{2} d x + \int 4 d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int 4 d x = 4 x

= \frac{x ^{5}}{5} - \frac{4 x ^{3}}{3} + 4 x

Add a constant to the solution

= \frac{x ^{5}}{5} - \frac{4 x ^{3}}{3} + 4 x + C

\int (4 x + 3) (2 x^{2} + 3 x)^{2} d x

\int \frac{12 x + 24}{x ^{2} + 4 x + 3} d x

3 x + 2

\frac{d y}{d x} = e^{8 x} + 10 y

\frac{d}{d x} (\frac{( 3 - 5 x ) ^{6}}{10})

What is the integral of x^4-4x^2+4 ?
The integral of x^4-4x^2+4 is (x^5)/5-(4x^3)/3+4x+C