What is the derivative of x^2e^x-e^x ?

The derivative of x^2e^x-e^x is 2xe^x+e^xx^2-e^x

What is the first derivative of x^2e^x-e^x ?

The first derivative of x^2e^x-e^x is 2xe^x+e^xx^2-e^x

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\frac{d}{d x} (x^{2} e^{x} - e^{x})

2 x e^{x} + e^{x} x^{2} - e^{x}

Solution steps

\frac{d}{d x} (x^{2} e^{x} - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} e^{x}) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (x^{2} e^{x}) = 2 x e^{x} + e^{x} x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x e^{x} + e^{x} x^{2} - e^{x}

x \to 6 lim (x π + x - 3)

\int 3 x^{2} (x^{3} + 4)^{10} d x

\frac{d}{d x} (\frac{5 x}{1 - x})

\frac{d}{d x} (2 x sin (2 x))

y^{^{''}} + 2 y^{^{'}} + 10 y = cos (t) + 0.739

What is the derivative of x^2e^x-e^x ?
The derivative of x^2e^x-e^x is 2xe^x+e^xx^2-e^x
What is the first derivative of x^2e^x-e^x ?
The first derivative of x^2e^x-e^x is 2xe^x+e^xx^2-e^x