What is area y=e^x,y=e^{2x},x=ln(4) ?

The answer to area y=e^x,y=e^{2x},x=ln(4) is 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=e^x,y=e^{2x},x=ln(4)

area

y = e^{x}, y = e^{2 x}, x = ln (4)

\frac{9}{2}

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{0}^{l n (4)} e^{x} - e^{2 x} d x

Solve

\int_{0}^{l n (4)} e^{x} - e^{2 x} d x : \frac{9}{2}

The area is:

= \frac{9}{2}

(cos (\frac{1}{x}))^{^{'}}

\int \frac{30 x ^{2} - 49}{x ^{4}} d x

\frac{\partial}{\partial x} (\frac{x}{x - 1})

x \to 0 lim (2 x^{2} cos (\frac{5}{x}))

f (x) = 5 x^{5} ln (x)

What is area y=e^x,y=e^{2x},x=ln(4) ?
The answer to area y=e^x,y=e^{2x},x=ln(4) is 9/2